Wednesday, May 21, 2014

Meeting Log

MEETING SUMMARY 17-APRIL-2014, DURING SCHOOL HOURS
HARRY - HERE
DEREK - HERE

-Discussed materials to use
Counterweight Dumbbell weights
Base Square
Arms Tetrahedrically connected to base
Trigger Cam be observed later
-Discussed some physics behind a 25 foot throw
Water balloon is on average about 3.15 inches in

diameter and .227 kilograms
Kinematics are involved
The ideal 45 degree throw to get 25 feet is

26.4 meters per second
Centripetal/Circular motion involved
Confusing, due to there being two systems

that interact dynamically with each other
Development of simulation suggested
-Discussed the use of Calculus
can be advantagous to development

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MEETING SUMARRY 10-MAY-2014, 10:00 AM TO 4:00 PM
HARRY - HERE
DEREK - HERE

Because this was only our first out-of-school

meeting, both of us knew that we had to get cracking if we

wished to complete the trebuchet within our allocated time.

To make matters worse, we spent many of our hours trying to

figure out a bunch of equations we didn't need, such as how

the acceleration due to gravity accumulates to velocity as

the position of the arm changes. After a clarification of the

rules, we found out that the requirements for the physics

applications simply calls for an explanation of force and

energy, not applied equations. However, we did apply calculus

to derive kinematics into a dandy equation that gives how

velocious an object needs to be in order to reach a certain

distance, given that the projectile's initial direction is 45

degrees above the horizontal. Here's the derivation (Please

note: "V" is the initial velocity in both dimensions):
     ⌠t
δy = │ (V - 9.8u) du
     ⌡0

or, δy = Vt - 4.9t²

δx = Vt

Vt = 4.9t² + δy

V = 4.9t + δy/t

V = 4.9(d/V) + δy(V/d)

1 = (4.9d/V²) + δy/d

d = (4.9d²/V²) + δy

d - δy = (4.9d²/V²)

4.9d²/(d-δy) = V²
     ____________
V = √4.9d²/(d-δy)

So now we have V, which is both the X velocity and Y

velocity. The actual tangental velocity is that number times

the square root of two:
              ____________
Vtangental = √9.8d²/(d-δy)

Once we store 9 meters into the distance-to-fly d value and

-1.5 meters into the change-in-y δy value, we get the speed

our water balloon needs in order to fly a grade-winning

distance: 8.695 meters per second.

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MEETING SUMMARY 14-MAY-2014, 2:00 PM TO 4:30 PM
HARRY - HERE
DEREK - HERE

Today, the both of us actually knew how to work

efficiently on the content of the project; as such, we were

able to get more stuff done, such as completing the written

portions of the physics applications of Force and Energy;

that leaves just Projectile motion left.

In addition, we devised many possible solutions to

some building restrictions. Through the use of pencils and

playdough, the both of us could much more easily explain our

ideas to each other. Several great ideas arisen from this.

For example, building the frame of the trebuchet in the shape

of a pyramid (rather than a prism) allows for much more

structural stability. Also, we decided that the use of

implementing a piece of skateboard would most certainly help

with the question of what our swinging arm will use to

actually swing.

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MEETING SUMMARY 18-MAY-2014, 12:30 AM TO 8:30 PM
HARRY - HERE
DEREK - HERE

This day saw our longest meeting to date, ranging an

entire eight hours from start to finish. Derek's father,

Norman Goodwin, aided in certain phases of construction that,

theoretically, are too dangerous for a pair of inexperienced

11th graders to try, but for the most part, we accomplished

most of the non-powertool-related building. After a good read

of a few more catapult videos from Youtube, we tried to aim

the ratio of L1 to L2 at roughly 2 to 5.

After seven hours of long, hard, sweaty work, the

catapult was finally ready for fine tuning. Unfortunately, we

ran into two problems with our catapult in doing this. For

one thing, we did not have a half-pound test ball; we had to

use a full-pound ball comprised of sand to test our

contraption, leaving us to guess if our balloons can

withstand the G-forces of our sling. For another, our

catapult could only throw our projectile about six feet.

What's worse, the reasons for the failure to launch remained

unclear until we reviewed the footage of the launch. With a

camera set to shoot frames at 80 Hz, we estimated that the

ball at launch farted out at 5.3 meters per second, a far cry

from the 8.7 meters per second we need. At the very least,

our angle of launch wound up almost perfectly correct, at

about 44 degrees from the horizon.

There are two possible reasons why our mechanism

malfunctioned:

• The counterweight wasn't heavy enough. To fix this

problem, we'd have to add extra mass onto the counterweight

to provide maximum centripetal acceleration.

• The sling's ropes were too long. Because of the

shape of the counterweight, L1's angle stalls at about 60 to

70 degrees below horizon from .7s to 1s after launch. To

maximize centripetal acceleration increasing the speed rather

than changing the angle, we would want our projectile to

launch exactly when the arm starts stalling. Instead, our

projectile takes until 1s to launch, destroying some much-

needed inertia just to get to a 45 degree angle. Shortening

the lengths of the ropes would most certainly solve this

problem, since the entire sling would swing around faster.

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MEETING SUMMARY 21-MAY-2014, 3:50 PM TO 8:10 PM
HARRY - HERE
DEREK - HERE

Because this was our last day to finish anything, we

worked more vigorously during this meeting than any other

meeting. Harry and Derek completely finished the trebuchet,

with the most noticeable modification (other than the paint)

being the counterweight's gain in mass; now, the catapult's

counterweight appears disorganized, but is actually extremely

sturdy. Dubbed the "CataPortal", our trebuchet juts out its

projectiles a whopping 32 feet.

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